.NET Framework only
This function performs a block update of an instance of the ADO.NET object System.Data.DataTable. This object may only be updated using an explicit row-wise loop, which is slow at the APL level. 2010⌶ implements an internal row-wise loop which is much faster on large arrays. Furthermore, the function handles NULL values and the conversion of internal APL data to the appropriate .NET datatype in a more efficient manner than can be otherwise achieved. These 3 factors together mean that the function provides a significant improvement in performance compared to calling the row-wise programming interface directly at the APL level.
Y is a 2, 3 or 4-item array containing:
The optional argument X is Boolean vector, where a 1 indicates that the corresponding column of Y[2] is a string from which the new values should be converted according to that column's data type.
Shown firstly for comparison is the type of code that is required to update a DataTable by looping:
⎕USING←'System' 'System.Data,system.data.dll' dt←⎕NEW DataTable ac←{dt.Columns.Add ⍺ ⍵} 'S1' 'S2' 'I1' 'D1' ac¨String String Int32 DateTime S1 S2 I1 D1 NextYear←DateTime.Now+{⎕NEW TimeSpan (4↑⍵)}¨⍳n←365 data←(⍕¨⍳n),(n⍴'odd' 'even'),(10|⍳n),⍪NextYear ¯2 4↑data 364 even 4 18-01-2011 14:03:29 365 odd 5 19-01-2011 14:03:29 ar←{(row←dt.NewRow).ItemArray←⍵ ⋄ dt.Rows.Add row} t←3⊃⎕ai ⋄ ar¨↓data ⋄ (3⊃⎕ai)-t 449
This result shows that this code can only insert roughly 800 rows per second (3⊃⎕AI returns elapsed time in milliseconds), because of the need to loop on each row and perform a noticeable amount of work each time around the loop.
2010⌶ does all the looping in compiled code:
dt.Rows.Clear ⍝ Delete the rows inserted above SetDT←2010⌶ t←3⊃⎕AI ⋄ SetDT dt data ⋄ (3⊃⎕AI)-t 4
So in this case, using 2010⌶ achieves over 90,000 rows per second.
Creating large arrays of DateTime objects in the workspace takes additional resources, and unless the data is already stored that way, it is not necessary to convert it to .NET objects. Data in ⎕TS format (7-element integer vector) or in a suitable character format may be used directly. The former is a specific Dyalog optimisation; the latter a feature of .NET Version 4.0. The following examples use numeric and character data for the dates:
months←12⍴31 ⋄ months[2 4 6 9 11]←29 30 30 30 30 n←⍴NextYear←7↑¨⊃,/(⍳12){(⊂2016,⍺),¨⍳⍵}¨months data←(⍕¨⍳n),(n⍴'odd' 'even'),(10|⍳n),⍪NextYear SetDT dt data
n←⍴NextYear←⊃,/(⍳12){(⊂'2016/',(⍕⍺),'/'),∘⍕¨⍳⍵}¨months data←(⍕¨⍳n),(n⍴'odd' 'even'),(10|⍳n),⍪NextYear SetDT dt data
In circumstances where .NET fails to accept character data automatically, it is possible to force conversion from character format to the corresponding .NET type.
If specified, the optional left argument X instructs the system to pass the corresponding columns of data to the Parse() method of the data type for those columns prior to performing the update.
In the following example, the left argument is not strictly necessary using .NET Version 4.0, but forces parsing for the data in the 4th column:
months←12⍴31 ⋄ months[2 4 6 9 11]←29 30 30 30 30 n←⍴NextYear←⊃,/(⍳12){(⊂'2016/',(⍕⍺),'/'),∘⍕¨⍳⍵}¨months data←(⍕¨⍳n),(n⍴'odd' 'even'),(10|⍳n),⍪NextYear 0 0 0 1 SetDT dt data
If applicable, Y[3] is a vector with as many elements as the DataTable has columns, indicating the value that should be converted to System.DBNull as data is written. For example, using the same DataTable as above:
t <null> odd 1 21-01-2010 14:50:19 two even 2 22-01-2010 14:50:19 three odd 99 23-01-2010 14:50:19 dt.Rows.Clear ⍝ Clear the contents of dt SetDT dt t ('<null>' 'even' 99 '')
Above, we have declared that the string '<null>' should be considered to be a null value in the first column, 'even' in the second column, and the integer 99 in the third.
Sometimes, you may have read a very large number of rows from a DataTable, but only want to update a single row, or a very small number of rows. Row indices can be provided as the fourth element of the argument to 2010⌶. If you are not using Y[3] explicitly, you can just use an empty vector as a placeholder. Continuing from the example above, we could replace the first row in our DataTable using:
SetDT←2010⌶ SetDT dt (1 4⍴'one' 'odd' 1 DateTime.Now) ⍬ 0
If you are experimenting with writing to a DataTable, note that you should call dt.Rows.Clear each time to clear the current contents of the table. Otherwise you will end up with a very large number of rows after a while.